Issue |
RAIRO-Oper. Res.
Volume 54, Number 2, March-April 2020
|
|
---|---|---|
Page(s) | 569 - 583 | |
DOI | https://doi.org/10.1051/ro/2019016 | |
Published online | 05 March 2020 |
Strategic behavior in the constant retrial queue with a single vacation
Donlinks School of Economics and Management, University of Science and Technology Beijing, Beijing 100083, China
* Corresponding author: yuzhang@ustb.edu.cn; yuzhang9006@163.com
Received:
26
November
2018
Accepted:
23
January
2019
We study customers’ joining strategies in an M/M/1 constant retrial queue with a single vacation. There is no waiting space in front of the server and a vacation is triggered when the system is empty. If an arriving customer finds the server idle, he occupies the server immediately. Otherwise, if the server is found unavailable, the customer enters a retrial pool called orbit with infinite capacity and becomes a repeated customer. According to the different information provided for customers, we consider two situations, where we investigate system characteristics and customers’ joining or balk decisions based on a linear reward-cost structure. Furthermore, we establish the social welfare of the system and make comparisons between the two information levels. It is found that there exist thresholds of system parameters such that the social planner would prefer revealing more information when the system parameter is greater than or less than the corresponding threshold.
Mathematics Subject Classification: 60K25 / 90B22
Key words: Queueing / Equilibrium strategies / Retrial / Single vacation / Social welfare
© EDP Sciences, ROADEF, SMAI 2020
Current usage metrics show cumulative count of Article Views (full-text article views including HTML views, PDF and ePub downloads, according to the available data) and Abstracts Views on Vision4Press platform.
Data correspond to usage on the plateform after 2015. The current usage metrics is available 48-96 hours after online publication and is updated daily on week days.
Initial download of the metrics may take a while.